Grading Student

problem-

HackerLand University has the following grading policy:

• Every student receives a  in the inclusive range from  to .
• Any  less than  is a failing grade.

Sam is a professor at the university and likes to round each student's  according to these rules:

• If the difference between the  and the next multiple of  is less than , round  up to the next multiple of .
• If the value of  is less than , no rounding occurs as the result will still be a failing grade.

For example,  will be rounded to  but  will not be rounded because the rounding would result in a number that is less than .

Given the initial value of  for each of Sam's  students, write code to automate the rounding process. For each , round it according to the rules above and print the result on a new line.

Input Format

The first line contains a single integer denoting  (the number of students). 
Each line  of the  subsequent lines contains a single integer, , denoting student 's grade.

Constraints

Output Format

For each  of the  grades, print the rounded grade on a new line.

Sample Input 0

4
73
67
38
33

Sample Output 0

75
67
40
33

Explanation 0

1. Student  received a , and the next multiple of  from  is . Since , the student's grade is rounded to .
2. Student  received a , and the next multiple of  from  is . Since , the grade will not be modified and the student's final grade is .
3. Student  received a , and the next multiple of  from  is . Since , the student's grade will be rounded to .
4. Student  received a grade below , so the grade will not be modified and the student's final grade is 33.
   
   
   solution

#include<bits/stdc++.h>

using namespace std;

/*

    *

    * Ratnadeep Sen

    * National Institute Of Technology Silchar -India (NITS)

    *

*/

int main(){

 int n;

 cin >> n;

 for(int a,x,i = 0; i < n; i++){

   cin >> a;

   if(a >= 38 && (x = (5 - (a % 5))) < 3)cout << a + x << endl;

   else cout << a << endl;

    }

}